Re: Pyramidiocy (was Re: Strange Maths)

Whittet (Whittet@shore.net)
29 Jul 1995 18:56:07 GMT

In article <1995Jul27.195118.4964@llyene.jpl.nasa.gov>, kdq@emoryi.jpl.nasa.gov says...
>
>Whittet@shore.net (Whittet) wrote:
>>Where are you getting the twenty integers from?
>>In the Great Pyramid you have
>>1.) the perimeter of the base
>>2.) the height
>>3.) the apothem
>
>My point is that with enough numbers to start, and by playing fast and
>loose with "exact" matches you can generate all the "significant"
>relationships you want.

That is a good point. What do we mean by fast and loose with the numbers
is it possible to establish a testable hypothesis here?

>
>There's no such thing, really, as "the" distance between two cities. Edge
>to edge? Center to center? Center as of when, calculated how? Around the
>curve or through the planet?

How about edge to edge.

For example suppose we use only whole integer Egyptian units of measure,
if we find recognizable whole integer increments of English measures,
in the principle proportions, edge to edge, like in the following example,
does that make what you would consider an adequate correlation?

> _
>Kevin D Quitt USA 91351-4454 96.37% of all statistics are made up

Some non "made up statistics."
>
units base base/2 height slope apothem perimeter

cubits 440.00 220 280.00 14 /11 356.09 1760.00
1/28 cubit 12320.00 6160 7840.00 14 /11 9970.52 49280.00
inches 9131.00 4565.5 5813.00 671 /527 7391.53 36524.00
1/12 cubit 5280.00 2640 3360.00 14 /11 4273.08 21120.00
28/22 cubit 560.00 280 356.00 89 /70 452.92 2240.00
English ft 761.00 380.5 484.00 968 /761 615.66 3044.00
Stadia 752.00 376 479.00 479 /376 608.95 3008.00
Roman ft 741.00 370.5 472.00 944 /741 600.05 2964.00
1/24 cubit 10560.00 5280 6720.00 14 /11 8546.16 42240.00
1/8 cubit 3520.00 1760 2240.00 14 /11 2848.72 14080.00

units ratio slope pi

cubits 24 /1 14 /11 3.142857
1/28 cubit 6 /7 14 /11 3.142857
inches 436 /377 671 /527 3.141579
1/12 cubit 2 /1 14 /11 3.142857
28/22 cubit 132 /7 89 /70 3.146067 (Greek foot)
English ft 10560 /761 968 /761 3.144628
Stadia 660 /47 479 /376 3.139875
Roman ft 3520 /247 944 /741 3.139831
1/24 cubit 1 /1 14 /11 3.142857
1/8 cubit 3 /1 14 /11 3.142857

units base base/2 height apothem perimeter phi

cubits 440.00 220 280.00 356.09 1760.00 1.618181818
1/28 cubit 12320.00 6160 7840.00 9970.52 49280.00 1.618590909
inches 9131.00 4565.5 5813.00 7391.53 36524.00 1.618996824
1/12 cubit 5280.00 2640 3360.00 4273.08 21120.00 1.618590909
28/22 cubit 560.00 280 356.00 452.92 2240.00 1.617571429
English ft 761.00 380.5 484.00 615.66 3044.00 1.618028909
Stadia 752.00 376 479.00 608.95 3008.00 1.619547872
Roman ft 741.00 370.5 472.00 600.05 2964.00 1.619568151
1/24 cubit 10560.00 5280 6720.00 8546.16 42240.00 1.618590909
1/8 cubit 3520.00 1760 2240.00 2848.72 14080.00 1.618590909

Here I have used just the base, height, apothem and perimeter of the Great Pyramid
in units based on even integer fractions of a cubit to see what proportions are
expressed. Note all base, height and perimeter measures are in even units.
The best match for all factors is in cubits, no other unit of measure works
as well

No matter how you measure it the PI relation is a given
In every case the apothem divided by half the base is
close to 1.6181 or phi, but closest measured in cubits or feet

you will note that the perimeter in cubits gives the number of yards in a mile.
the perimeter in inches gives the number of days in a century
the base in units of 1/12 cubit gives the number of feet in a mile
the square on the height is equal to the area of the sloped side

The least best correlation is with the apothem to a stadia, 608.73 English feet
a stadia is supposed to be 24902.72727/360*600 and to equal 600 feet

The most startling results are

units base base/2 perimeter height apothem

cubits 440.00 220 * 1760.00 * 280.00 356.09
1/24 cubit 10560.00 * 5280 * 42240.00 6720.00 8546.16
1/12 cubit * 5280.00 * 2640 21120.00 3360.00 4273.08
1/8 cubit 3520.00 * 1760 * 14080.00 2240.00 2848.72
inches 9131.00 4565.5 *36524.00 * 5813.00 7391.53

and indeed

100 x 365.24 x 24 x 60 x 60/ 24902.72727 x 5280 x 12 x 2 = 1

there are twice as many seconds in a century as inches
in the circumference of the earth at the equator

and

360/24902.72727 = 5280/365.24 x 1000

the length of an Egyptian year in days divided
by the circumference of the Earth at the equator in miles
is directly proportional to the number of feet in a mile
divided by the number of days in a millenia

Steve